Question

tanA=x/y, then cosA is equal to​

Answer 1

Answer:

sec^2A = 1 + tan^2A = 1+ (x/y)^2 = (y^2 + x^2)/y^2

1/cos^2A = (y^2 + x^2)/y^2

cos^2A = y^2/((y^2 + x^2)

cosA = y/√(y^2 + x^2)

Answer 2

Cos A = $\frac{Y}{\sqrt{X^{2} +Y^{2} } }$ .

Step-by-step explanation:

Step 1 - Formula used-

• H = $\sqrt{P^{2} +B^{2} }$ this formula is used for finding Hypotenuse as H in a right angled triangle in this formula P is for Perpendicular and B is for Base of right angled triangle.

• Cos A = $\frac{B}{H}$

Step 2- Given Data

we are given with the value of Tan A which is ,

Tan A = $\frac{X}{Y}$

Tan A means $\frac{P }{B}$  , a right angled triangle have a perpendicular , a base and a Hypotenuse we have the values of Perpendicular and Base which are X and Y respectively.

By using formula of Hypotenuse we get ,

H = $\sqrt{X^{2} +Y^{2} }$

Step 3 - Calculation of Cos A

By using above formula for Cos A we get,

Cos A = $\frac{Y}{\sqrt{X^{2} +Y^{2} }}$  and this is our answer for this question.