Question

Tanav is 1/6 times as old as his mother.After 6 years his mother will be 6 years more than thrice his age.find the present age.​

Answer 1

Step-by-step explanation:

let T be Tanav's age and M be his mother's age.

Tanav is 1/6 times his mother's age = (1/6)*M

After 6 yrs,

(M+6) = 3(T+6)

(M+6) = 3((M/6)+6)

M = 24

T = M/6 = 24/6 = 4

Answer 2

Given: Tanav's  present age (x) is $\frac{1}{6}$ his mother's present age (y)

After 6 years, his mother will be 6 times more than thrice his age

To find: Tanav and his mother's present age (x and y respectively)

Step-by-step explanation:

Let Tanav's present age be x

Let Tanav's mother's present age be y

• According to first case x = $\frac{1}{6}$ . y                  (1)
• After 6 years Tanav's age will be x+6

• According to 2nd case y + 6 = 3(x + 6) + 6        (2)

Solving equation(2) y = 3x + 18         (3)  ( 6 gets subtracted from both sides)

Substituting value of y from equation (1) and (3)

⇒ 6x = 3x + 18                   ( x= $\frac{1}{6}$. y ⇒ y=6x)

⇒ 3x = 18

⇒ x=6

∴ y= 36

Hence present age of Tanav is 6 and present age of his mother is 36.