Tangents from outside point P to a circle with Centre o r p a and P V were angle aob is 80 then angle APB is tangents from an outside point P to a circle with Centre O and P A and P B were angle A B equal to 80 degree then angle APB is
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Answer: 100°
Step-by-step explanation: Radius is perpendicular to t tangent at t point of contact.
<OAP=<OBP=90°
In quadrilateral OAPB all angles are 360°.
By angle sum property, <APB=100°
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