Math, asked by archiparmar123, 11 months ago

If one of the zeroes of the given polynomial p(x) = 3x^3 - 5x^2 - 11x - 3 is -1/3, then find the other zeroes ​

Answers

Answered by naminandhu007
1

Answer:-1,3

Step-by-step explanation: haii!!

One zero is -1/3.

x=-1/3

3x+1=0

Divide p(x) by 3x+1

We get quotient as x^2-2x-3.

By splitting t middle term, we get

x^2-3x+x-3=0

(x+1)(x-3)=0

The zeroes are -1/3, 3, -1

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