Question

Tangents PA and PB are drawn to a circle with centre O from a point P outside the circle. Prove that angleOPA =angle OAM

Answer 1

Sloution:

constitution - join O with P.

prof:
OA = OB (radius of circle)

PA = PB (Tangent drawn from same point on circle are equal)

OP = OP (common side)

=> triangleOAP = traingleOPB (SSS congruence criterion)

so, angle oap = angle obp (C.P.C.T)

Hence, proved

Answer 2

Triangle OAP=Triangle OPB(SSS Congruent criteria
CPCT