Question

Tangents PA and PB of (0,r) touches the circle at A and B. If angle AOB=80 find angle OPB​

Answer 1

Answer:

Correct option is B)

In □AOBP,

∠AOB+∠A+∠B+∠APB=360

o

...Angle sum property of quadrialteral

∠AOB=360

∘

−90

∘

−90

∘

−80

∘

=100

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