Tangents PQ and PR are drawn from an external point P to a circle with centre O, such that angle RPQ=30°. A chord RS is drawn parallel to the tangent PQ. Find angle RQS.
Answer is 30°
but solve karke btao jaldi please
Answers
Answer:
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Step-by-step explanation:
PQ = PR
Since tangents drawn from an external point to a circle are equal.
And PQR is an isosceles triangle
thus, ∠RQP = ∠QRP
∠RQP + ∠QRP + ∠RPQ = 180° [Angle sum property of a triangle]
2∠RQP + 30° = 180°
2∠RQP = 150°
∠RQP = ∠QRP = 75°
∠RQP = ∠RSQ = 75° [ Angles in alternate Segment Theorem states that angle between chord and tangent is equal to the angle in the alternate segment]
RS is parallel to PQ
Therefore ∠RQP = ∠SRQ = 75° [Alternate angles]
∠RSQ = ∠SRQ = 75°
Therefore QRS is also an isosceles triangle
∠RSQ + ∠SRQ + ∠RQS = 180° [Angle sum property of a triangle]
75° + 75° + ∠RQS = 180°
150° + ∠RQS = 180°
∠RQS = 30°
Answer:
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