Tank is fitted with 8 pieces sum of which date fill the tank and other that empty the tank is of the pipe that fills the tank fills it in 8 hours while each of those that empty the tank empty in 6 hours what happen when the tank is full
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How mate!!
Let the number of fill pipes be 'n'. Therefore, there will be (8 - n) waste pipes.
Each fill pipe fills 18th of the tank in an hour. So, "n" fill pipes will fill n8th of the tank in an hour.
Each waste pipe drains 16th of the tank in a hour.
So, \"8 - n\" waste pipes will drain 8−n6th of the tank in an hour.
Keeping these 8 pipes open results in 16th of the tank being drained every hour.
Hence, n8−8−n6=−16
Solving for n, we get n = 4.
Therefore, there are 4 fill pipes and 4 waste pipes.
Hope it helpful
Let the number of fill pipes be 'n'. Therefore, there will be (8 - n) waste pipes.
Each fill pipe fills 18th of the tank in an hour. So, "n" fill pipes will fill n8th of the tank in an hour.
Each waste pipe drains 16th of the tank in a hour.
So, \"8 - n\" waste pipes will drain 8−n6th of the tank in an hour.
Keeping these 8 pipes open results in 16th of the tank being drained every hour.
Hence, n8−8−n6=−16
Solving for n, we get n = 4.
Therefore, there are 4 fill pipes and 4 waste pipes.
Hope it helpful
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