Question

tantheeta=Qsina/p+Qcosa prove that tan(a-theeta)=psina/Q+pcosa
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Answer 1

P sinA - q cosA / P sin A +q cos Adivide both numerator and denominator by cosA= p tanA - q / p tan A + qNow, use to given relation, tan A = p/q substitute to get the required answer .(A = theta 2.8 )

Answer 2

P sinA - q cosA / p sin A + q cos ADivide both numerator and denominator by cosA= p tanA - q / p tan A + qNow, use the given relation, tan A = p/qSubstitute to get the required answer. (A = theta

2.8