tantheta+4/tantheta =5 find sintheta and costheta
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hi ✌️
here is your answer....
Let tan theta= A
then , according to the question
A + 4/A =5
A^2-5A+4=0
(A-4) (A-1)=0
A=4 or 1
hence, tan theta = 4 or 1
we know that
1+tan^2 theta=sec^2 theta......(1)
so, tan^2 theta = 1 or 16
putting the value of tan they in eq.....(1)
case-1
======
1+1=sec^2theta
cos theta= 1/ root2
case-2
======
1+16= sec^2 theta
cos theta=1/root 17
again ,
sin^2 theta+cos^2theta=1
sin^2theta=1-cos^theta
hence sin theta=1/root2 or 4/root 17
hope it will help you ☺️
be BRAINLY ☑️
I write in shortly but in above picture⬆️⬆️⬆️⬆️⬆️
I will write perfectly.....
here is your answer....
Let tan theta= A
then , according to the question
A + 4/A =5
A^2-5A+4=0
(A-4) (A-1)=0
A=4 or 1
hence, tan theta = 4 or 1
we know that
1+tan^2 theta=sec^2 theta......(1)
so, tan^2 theta = 1 or 16
putting the value of tan they in eq.....(1)
case-1
======
1+1=sec^2theta
cos theta= 1/ root2
case-2
======
1+16= sec^2 theta
cos theta=1/root 17
again ,
sin^2 theta+cos^2theta=1
sin^2theta=1-cos^theta
hence sin theta=1/root2 or 4/root 17
hope it will help you ☺️
be BRAINLY ☑️
I write in shortly but in above picture⬆️⬆️⬆️⬆️⬆️
I will write perfectly.....
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aniketgupta19:
nice brain yarr
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