Question

tanx=(-4/3) x in second quadrant value of sin2x,cos2x

Answer 1

cos x=-3/4
sin2x=2sinx cosx
sin2x=(8/5)(-3/5)
sin2x=-24/25
cos 2x=2cos² x-1
cos2x=2x 9/25-1
cos2x=-7/25
tan2x=sin2x/cos 2x=24/7