Math, asked by vanshjangra, 9 months ago

tanx + cotx = secx cosecx​

Answers

Answered by prashanttyagi199931
3

Answer:

Hey ur answer is

LHS

tanx+cotx

sinx/cosx+cosx/sinx

sin^2x+cos^2x/cosxsinx

1/cosxsinx

1/cosx.1/sinx

secx.cosecx

hope it helps u

Answered by Anonymous
10

\rule{300}2

Correct Question:

Prove that

tanx + cotx = secx cosecx​

\rule{300}2

Your Answer:

Solving LHS

tanx + cotx

=\frac{\sin x}{\cos x}+ \frac{\cos x}{\sin x}\\ \\=\frac{\sin x^{2}+ \cos x^{2}}{\sin x\times\cos x}\\ \\=\frac{1}{\sin x \times \cos x}\\ \\=\csc x \times \sec x

RHS

secx. cosecx

So, LHS=RHS

proved

\rule{300}2

\Huge{\red{\underline{\text{More Information:}}}}

The trigonometric formulas used here are

  • 1/ sin x = cosec x
  • 1/ cos x = sec x
  • tan x = sin x / cos x
  • cot x = cos x / sin x
  • sin²x + cos²x = 1

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