Math, asked by kartiksharma0711, 1 month ago

tanx+secx-1/tanx-secx+1=1+sinx/cosx

Answers

Answered by pv4231840

0

Answer:

tanx+secx-(sec^2x-tan^2x) /tanx-secx+1

(tanx+secx) (1+tanx-secx) /(tanx-secx+1)

sinx/cosx+1/cosx

sinx+1/cosx

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