tanx+secx-1/ tanx-secx +1 =1+sinx/cosx can this question be done by converting tanx and secx into sinx and cosx
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Yes it can be solved by converting tanx and secx into sinx and cosx. Or you can also observe that sec^2(x)-tan^2(x) =1 then you can easily find secx-tanx =1/(secx+tanx) by a^2-b^2=(a-b)(a+b)
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