Math, asked by ranbeerst99, 1 year ago

tanx + tan2x +tan3x = tanxtan2xtan3x

Answers

Answered by nandhinimouli

188

tan x + tan 2x + tan 3x - tan x tan 2x tan 3x = 0
tan x + tan 2x + tan 3x ( 1 - tan x tan 2x ) = 0
tan x + tan 2x = - tan 3x ( 1 - tan x tan 2x )
( tan x + tan 2x )/ ( 1 - tan x tan 2x ) = - tan 3x
tan 3x = - tan 3x
2 tan 3x = 0
tan 3x = 0
3x = 2kpi where k = 0, 1,2,3,4,5,..............
x = 2 k pi/3 where k = 0 , 1, 2 ,3 , 4 , 5 , 6..............

nandhinimouli: Click on Thank you if u find it useful

Answered by ababhimanyu11

Answer:

Step-by-step explanation:

tan x + tan 2x + tan 3x - tan x tan 2x tan 3x = 0

tan x + tan 2x + tan 3x ( 1 - tan x tan 2x ) = 0

tan x + tan 2x = - tan 3x ( 1 - tan x tan 2x )

( tan x + tan 2x )/ ( 1 - tan x tan 2x ) = - tan 3x

tan 3x = - tan 3x

2 tan 3x = 0

tan 3x = 0

3x = 2kpi where k = 0, 1,2,3,4,5,..............

x = 2 k pi/3 where k = 0 , 1, 2 ,3 , 4 , 5 , 6.............

Previous Question

Next Question