Tanya's toy is deciding on dimensions for their boxes to store building blocks they want the box to have a volume of 48 inch^3 A. Find all the possible whole number dimensions for a box with a volume of 48 inch^3 (raise to 3) B. Which whole number dimensions would require the most wrapping paper to cover? C. Which whole number dimensions would require the least wrapping paper to cover?
Answers
(A) The possible dimensions are
1 inch × 2 inch × 24 inch
2 inch × 2 inch × 12 inch
3 inch × 2 inch × 8 inch
4 inch × 2 inch × 6 inch
4 inch × 4 inch × 3 inch
1 inch × 4 inch × 12 inch
1 inch × 8 inch × 6 inch
1 inch × 1 inch × 48 inch
B) The dimensions with highest surface area will require the most wrapping paper which will be 1 inch × 1 inch × 48 inch
C) The dimensions with least surface area will require least wrapping paper which will be 4 inch × 4 inch × 3 inch
Step-by-step explanation:
Volume of the box to store building blocks = 48 inch³
If the length, breadth and height of the box be l, b, h then
Volume of box = l × b × h
Surface area of the box = 2(lb + bh + hl)
If l, b, h are whole numbers then
Possible values of l × b × h and their surface areas are
1 × 2 × 24 Surface area = 2(1 × 2 + 2 × 24 + 1 × 24) = 148 inch²
2 × 2 × 12 Surface area = 2(2 × 2 + 2 × 12 + 12 × 2) = 104 inch²
3 × 2 × 8 Surface area = 2(3 × 2 + 2 × 8 + 8 × 3) = 92 inch²
4 × 2 × 6 Surface area = 2(4 × 2 + 2 × 6 + 6 × 4) = 88 inch²
4 × 4 × 3 Surface area = 2(4 × 4 + 4 × 3 + 3 × 4) = 80 inch²
1 × 4 × 12 Surface area = 2(1 × 4 + 4 × 12 + 12 × 1) = 128 inch²
1 × 8 × 6 Surface area = 2(1 × 8 + 8 × 6 + 6 × 1) = 124 inch²
1 × 1 × 48 Surface area = 2(1 × 1 + 1 × 48 + 48 × 1) = 194 inch²
The dimensions with highest surface area will require the most wrapping paper which will be 1 × 1 × 48
The dimensions with least surface area will require least wrapping paper which will be 4 × 4 × 3
Hope this answer is helpful.
Know More:
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