Tap a fills a tank in 10 hours and b can fill it in 15 hours. both are opened simultaneously. sometimes later tap b was closed, then it takes total 8 hours to fill up the whole tank. after how many hours b was closed?
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Pipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes ... Part filled by B in 1 hour = 1/10 ... So it will take further 8 mins 15 seconds to fill the bucket.
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Answer: 3 Hours
Step-by-step explanation: Total unit of work L.C.M of 10 & 15 i.e 30 unit. work done per hour by A= 3 unit & by B= 2 unit. now let x hours taken by A to fill up the remaining tank. so in x hours, 3x unit has been filled. work done in 1 hour by (a+b) is 5 unit. Total time taken is 8 hours. so in (8-x) hours a+b can fill up 5(8-x).
now,
3x + 5(8-x) = 30 => x= 5 hours. then B was closed for 8-5=3 hours
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