Question

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* The age af is girls in a group are is years
Yomonths, 15 years 8 months, 14 years 9 menthe.
15 years 3 monthe, 14 years 8 months find the
average age per cirls in the group.​

Answer 1

${\fbox{\boxed {\huge{\mathbb{\red{ANSWER:-}}}}}}$

✏ ${\underline{\underline{\large \tt{Given}}}}:-$

>>>Age of Girls

1. 15 years 8 month
2. 14 years 9 month
3. 15 years 3 month
4. 14 years 8 month

✏ ${\underline{\underline{\large \tt{Find}}}}:-$

Average of girls age

✏ ${\underline{\underline{\LARGE \tt{ Solution}}}}:-$

${\Rightarrow {\small{\tt Age\: of \: first \: girl : - 15 \: year \: 8 \: months}}}$

${\huge{\star}{\large\boxed{\tt12 \:months = 1 \: year}}}$

So,

$\tt: \implies15 + \frac{8}{12} \\ \tt: \implies \frac{180 + 8}{12} \\ :\implies \boxed {\tt\frac{188}{12}} \:....... \tt{equation \: 1}$

${\Rightarrow{\small{\tt Age \: of \: second\: girl : - 14\: year \: 9\: months}}}$

$\tt: \implies14 + \frac{9}{12} \\ \tt: \implies \frac{168 + 9}{12} \\ :\implies \boxed {\tt\frac{177}{12}} \:....... \tt{equation \: 2}$

${\Rightarrow{\small{\tt Age \: of \: third\: girl : - 15\: year \: 3\: months}}}$

$\tt: \implies15 + \frac{3}{12} \\ \tt: \implies \frac{180+ 3}{12} \\ :\implies \boxed {\tt\frac{183}{12}} \:....... \tt{equation \: 3}$

${\Rightarrow{\small{\tt Age \: of \: fourth\: girl : - 14\: year \: 8\: months}}}$

$\tt: \implies14+ \frac{8}{12} \\ \tt: \implies \frac{168+ 8}{12} \\ :\implies \boxed {\tt\frac{176}{12}} \:....... \tt{equation \: 4}$

We have to find the average age of per girl in the group.

${\small{\boxed{\tt{Average \: of \:4\: girls =\frac{ sum\: of\: all \: girls}{total\: no.\: of \:girls}}}}}$

$: {\implies{\large {\tt\frac{ \frac{188}{12 } + \frac{177}{12} + \frac{183}{12} + \frac{176}{12}}{5}}}}</p><p>$

$: \implies \tt\frac{ 724}{60}$

${:{\implies \: \pink{ \fbox \blue{\boxed{\tt12.06}}}}}$

${\boxed {\huge{\green{\mathcal{BeBrainly}}}}}$