Question

Tarun has 48 sweets.He gave 15 of them to Jai and 13 to Dhruv. What is the fraction of the original 48 sweets left with Tar​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Total sweets = 48

No. of sweets given to Jai = 15

No. of sweets given to Dhruv = 13

No. of sweets left to Tarun = 48 - ( 15+13)

= 48 - 28

= 20 sweets

No fraction of sweets left to Tarun with no of original sweets is

$= \frac{20}{48}$

$= \frac{5}{12}$

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