Question

te least number by wic 12348must be divided so to ave te quationt as a perfect square is

Answer 1

12348=2*2*3*3*7*7*7

          =(2^2)*(3^2)*(7^2)*7

Since, 7 is not in pair so, the smallest no. by which 12348 is 7

So, the square root of the quotient is = Math. sqrt (12348/7)

                                                              = Math.sqrt(1964)

                                                              = 2*3*7

                                                              = 42