te present ages of A and B is 4:5 .18 yrs ago this ratio was 11:16 .The sum of the present ages is
Answers
Required Answer :
The sum of present ages of A and B = 90 years
Given :
- Ratio of the present ages of A and B = 4 : 5
- The ratio of their ages, 18 years ago = 11 : 16
To find :
- Sum of the present ages of A and B
Solution :
Let,
- Present age of A = 4x
- Present age of B = 5x
Their ages 18 years ago,
⇒ Age of A = 4x - 18 years
⇒ Age of B = 5x - 18 years
According to the question,
⇒ Age of A/Age of B = 11/16
⇒ (4x - 18)/(5x - 18) = 11/16
⇒ 16(4x - 18) = 11(5x - 18)
⇒ 64x - 288 = 55x - 198
⇒ 64x - 55x = - 198 + 288
⇒ 9x = 90
⇒ x = 90/9
⇒ x = 10
Substituting the value of x in the present ages of A and B :
⇒ Present age of A = 4x
⇒ Present age of A = 4(10)
⇒ Present age of A = 40 years
⇒ Present age of B = 5x
⇒ Present age of B = 5(10)
⇒ Present age of B = 50 years
The sum of present ages of A and B :
⇒ 40 + 50
⇒ 90 years
Therefore,
- The sum of present ages of A and B = 90 years
Answer:
- The sum of their present ages is 90 years
Step-by-step explanation:
Given:
- The present ages of A and B are in the ratio 4 : 5
- 18 years ago the ratio of their ages was 11 : 16
To Find:
- The resultant sum of their present ages
Assumptions:
- Let A's present age be 4x
- Let B's present age be 5x
According to the question:
By cross multiplying :
Present ages of A will be :
→ The present age of A = 4x
→ The present age of A = 4 ( 10 )
→ The present age of A = 40 years
Present ages of B will be :
→ The present age of B = 5x
→ The present age of B = 5(10)
→ The present age of B = 50 years
Sum of the Present ages of them will be :
→ The sum of their present ages = 4x + 5x
→ The sum of their present ages = 40 + 50
→ The sum of their present ages = 90 years
Therefore :
- The sum of the present ages of A and B = 90 years
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