Question

Teachers and students are selected at
random to make two teams of 30 members
each on sport day to participate in the event
of 'Tug of War.' The numbers of volunteers
are as follow
Teachers
Students
Male
Female
Male
Female
12
18
20
10
Find the probability that the person chosen
at random
(i) is a male teacher.
(ii) is a female student.​

Answer 1

Answer:

total outcome 60

no of outcome 20

p(e)=n/m

=20/60

=1/3

2) total outcome 60

no of outcome 10

p(e)=10/60

=1/6

Answer 2

• The probability that the person chosen at random is a male teacher is 1/5

• The probability that the person chosen at random is a female student is 1/6

Given :

Teachers and students are selected at random to make two teams of 30 members each on sport day to participate in the event of 'Tug of War.' The numbers of volunteers are as follow

Teachers

Students

Male

Female

Male

Female

12

18

20

10

To find :

• The probability that the person chosen at random is a male teacher

• The probability that the person chosen at random is a female student

Solution :

Solution :Step 1 of 3 :

Find total number of possible outcomes

Total number of teachers and students in two teams

= 12 + 18 + 20 + 10

= 60

Step 2 of 3 :

Find the probability that the person chosen at random is a male teacher

Let A be the event that the person chosen at random is a male teacher

Total number of male teacher = 12

So total number of possible outcomes for the event A is 12

So the probability that the person chosen at random is a male teacher

= P(A)

$\displaystyle \sf{ = \frac{12}{60} }$

$\displaystyle \sf{ = \frac{1}{5} }$

Step 3 of 3 :

Find probability that the person chosen at random is a female student

Let B be the event that the person chosen at random is a female student

Total number of female student = 10

So total number of possible outcomes for the event B is 10

So the probability that the person chosen at random is a female student

= P(B)

$\displaystyle \sf{ = \frac{10}{60} }$

$\displaystyle \sf{ = \frac{1}{6} }$