Question

Team A won 60% matches. Team B Won 1 more matches then Team A. and won only one match. If Team B played 14 matches then find
(a) No. of matches played by team A
(b) No. of Matches Tam A looses
(c) Presentage of matches Team A won
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Answer 1

Answer:

I think all of those who used binomials and got 0.71 are wrong. That's because although the expansion of the binomial allows for the possibility that B can be in the last position, in this problem team B can never win the last game of a series (since team A wins the series). Here is how I have it:

probability of A winning in 4 games: 0.6^4 = 0.1296

probility of win in 5 games: (.05184) x 4 = .20736

probability of win in 6 games: (.020736) x 10 = .20736

probability of win in 7 games= (.00082944) x 10 = .0082844

adding those up I got p = 0.627264

The “0.71” people counted one too possibilities for 5, 6, and 7 game series and when I add in those extra games to my answer I got 0.627264 + .0808704 = .7081344, or essentially their answer of 0.71. I have it as essentially 0.63 or 63%.