Question

Teena is 3 years younger than his brother . If the sums of their ages is 32 years . What are their present ages ​

Answer 1

$\huge\colorbox{pink}{Answer ✔}$

Teena is 14.5 yrs old.

Her brother is 17.5 yrs old.

$\huge\colorbox{pink}{Explanation ✔}$

Ler her brother age be +3

Teena age be x

$x + x + 3 = 32 \\ 2x + 3 = 32 \\ 2x = 29 \\ x = 14.5 \\ x + 3 = 17.5$

Hope it helps you ☺️☘️

Answer 2

Solution:-

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Here, the question has told that Teena is 3 years younger than his brother. If the sum of her and her brother's age is 32 years. What are their present ages.

ANSWER:-

• Teena's age is 14.5.
• Her brother's age is 17.5.

GIVEN:-

• Teena is younger than her brother = 3 years
• Sum of their ages = 32 years

TO FIND:-

• Their recent ages are = ?

ACCORDING TO THE QUESTION:-

• Let the age of Teena's brother = (x + 3)
• Let the age of Teena be = x

➳ x + (x + 3) = 32

➳ x + x + 3 = 32

➳ 2x + 3 = 32

➳ Taking 3 to RHS, so it will become -3

➳ 2x = 32 - 3

➳ 2x = 29

➳ Taking 2 to RHS, it will go in divide (÷).

➳ x = 29 / 2

➳ x = 14.5

Hence Teena's age is 14 years 5 months (14.5 years).

• Finding her brother's age:-

➳ We assumed his brother's age = (x + 3)

➳ x = 14.5

➳ Her brother's age = 14.5 + 3

➳ Her brother's age = 14.5 + 3 = 17.5

➳ Her brother's age= 17.5 years

Hence, her brother's age is 17 years 5 months (17.5).

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