Question

tel answer of 2nd q fast

I'll mark it as brainliest ​

Answer 1

solution

ang(AMX)+ang(CMX)+ang(CMY)+ang(AMY)=360°

=>ang(AMX)+ang(AMY)+ang(AMX)+ang(AMY)=360°

=>2(ang(AMX)+ang(AMY))=360°

=>ang(AMX)+ang(AMY)=180°

= ang(XMY)=180°

therefore..XMY is a straight line....(proved)

[n.b.:-ang(CMX)=ang(AMY) =vertically opposite angles.

ang(CMY)=ang(AMX)=vertically opposite angles]