Math, asked by 18010160, 5 months ago

Tel me 10 table and 11 table​

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Answered by syedasad3764
1

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Answered by XxMyselfBhootxX
1

\huge\sf{ϙᴜᴇsᴛɪᴏɴ:-}

How many cubic centimetres of iron are there in an open box whose external dimensions are 36m, 25cm and 16.5cm, the iron being 1.5cm throughout? If 1 cm³ of iron weight 15g find the weight of empty box in kilograms.

\huge\sf{sᴏʟᴜᴛɪᴏɴ:-}

\green{\sf{The~external~length=36cm}}

\green{\sf{The~external~breadth=25cm}}

\green{\sf{The~external~height=16.5cm}}

\green{\boxed{\boxed{\sf{The~external~volume=Length×Breadth×Height}}}}

\green{\sf\leadsto{The~external~volume=36cm×25cm×16.5cm}}

\green{\sf{The~external~volume=14,850cm³}}

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\purple{\sf{The~internal~length=36-[2×1.5]}}

\purple{\sf{\leadsto{The~internal~length=33cm}}}

\purple{\sf{The~internal~breadth=25-[2×1.5]}}

\purple{\sf{\leadsto{The~internal~breadth=22cm}}}

\purple{\sf{The~internal~height=16.5-1.5}}

\purple{\sf{\leadsto{The~internal~height=15cm}}}

\purple{\sf{The~internal~volume=Length×Breadth×Height}}

\purple{\sf{\leadsto{The~internal~volume=33cm×22cm×15cm}}}

\purple{\sf{\leadsto{The~internal~volume=10,890cm³}}}

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\tt{\red{Volume~of~iron~in~the~box=14,850-10,890}}

\tt{\red{Volume~of~iron~in~the~box=3969cm³}}

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\orange{\sf{Weight~of~1m³~of~iron = 15grams}}

\orange{\sf{Weight~of~3960cm³~of~iron = (15×3960)=59400g}}

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\sf{\orange{1kg = 1000 g}}

\sf{\orange{\therefore59400g=\frac{594\cancel{00}}{10\cancel{00}}kg}}

\implies{\orange{\boxed{\boxed{\sf{59.4kg}}}}}

The weight of empty box in kg = 59.4 kg

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