Question

TELL CORRECT ANSWER PLS IT'S A REQUEST ​

Answer 1

Answer:

The value of a is 22/3

To solve :

Use factor theorem

Solution :

Let $P(x)=x^3+2x^2-3ax-8$

Solving

As it is divisible by x-4, $P(4)$ is 0.

$P(4)=88-12a$, by substitution

$88-12a=0$ ∴$a=\frac{22}{3}$

Therefore, the value is 22/3

Answer 2

Step-by-step explanation:

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$\huge{\green{\mathfrak{Answer}}}$

Let g(x) = x - 4 = 0.

So, x = 4

Now, Let$p(x) = x^{3}+2x^{2}-3ax-8$.

So, p(x) will be a multiple of g(x) if p(4)=0.

So,

=>$p(4)= 4^{3}+2×4^{2}-3a×4-8 = 0$

=>$64 +32 -12a-8= 0$

=>$96 -12a-8=0$

=>$88-12a=0$

=>$12a = 88$

=>$a =\dfrac{88}{12}$

So, $a=\dfrac{22}{3}$

$\huge\red{\boxed{Answer = \dfrac{22}{3}}}$