Question

tell fast please...............

Answer 1

a + b / √ ab = 6

a + b = 6√ab

squaring on both sides

a²+b²+2ab = 36ab

a²+b²=34ab

a² = 34ab - b²

a² = b ( 34a - b) ... eqn(1)

we also obtain

b² = a ( 34b - a) ... eqn(2)

Now equation 1/2 .

a² / b² = b( 34a - b) / a ( 34b - a)

a³ / b³ = 34a - b / 34b-a

a/b = $\sqrt[3]{ \frac{34a - b}{34b -a } }$

Answer 2

Here is Ur answer.............!