Math, asked by aditya007rangari, 1 year ago

tell me answer fast please

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Answered by hukam0685
1

let \:  \frac{1}{3x + y}  = u \\  \frac{1}{3x - y}  = v \\ u + v =  \frac{3}{4}  \\ 4u + 4v = 3 \:  \:  \:  \:  \: eq1 \\  \frac{u}{2}  -  \frac{v}{2}  =  \frac{ - 1}{8}  \\ 4u - 4v =  - 1 \:  \:  \:  \:  \: eq2 \\ add \: both \: eq \\ 8u = 2 \\ u =  \frac{1}{4}  \\ 4 \times  \frac{1}{4}  + 4v = 3 \\ 4v = 2 \\ v =  \frac{1}{2}  \\  \\ put \: these \: value \: in \: initial \: assumption \\  \frac{1}{3x + y}  =  \frac{1}{4}  \\  3x + y = 4 \\ \frac{1}{3x - y}  =  \frac{1}{2}  \\ 3x - y = 2 \\ on \: adding \: both \: eq \\ 6x = 6 \\ x = 1 \:  \:  \: ans \\ 3x - y = 2 \\ 3 - y = 2 \\  - y = 2 - 3 \\ y = 1 \:  \:  \: ans
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