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IN ENGLISH:
let ,
3rd digit is X
acq 2nd digit is 8-X
1st digit is X/2
4th digit is X/2 × 8-X=(8x-x²)/2
According to question X/2 +(8-X)+X+(8x-x²)/2=12
=>(x+16-2x+2x+8x-x²)/2=12
=>16+9x-x²= 24
=>x²-9x+8=0
=>x²-8x-x+8=0
(x-8)(x-1)=0
x is 8 or 1
The digit is 4080
We can't taken 1 as 3rd digit because 1st digit is half of 3rd so .
IN HINDI:
तीसरा अंक X है
acq 2nd अंक 8-X है
पहला अंक X / 2 है
चौथा अंक X / 2 × 8-X = (8x-x /) / 2 है
प्रश्न के अनुसार X / 2 + (8-X) + X + (8x-x /) / 2 = 12
=> (X + 16-2x + 2x + 8x-x²) / 2 = 12
=> 16 + 9x-x² = 24
=> X²-9x + 8 = 0
=> X²-8x-x + 8 = 0
(एक्स-8) (एक्स 1) = 0
x 8 या 1 है
अंक 4080 है
हम 1 को 3 अंक के रूप में नहीं ले सकते क्योंकि 1 अंक 3 का आधा है।
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