Question

tell me question no a

Answer 1

x²+4kx + (k²-k+2)=0
x² + 4kx+ (k² -2k+k+2)=0
x²+4kx + ( k(k-2)-1(k-2) ) =0
k =2
k =1
solve

Answer 2

The given quadratic equation :-

=> x² + 4kx + (k² - k + 2) = 0

Here we have, a = 1, b = 4k and c = (k² - k + 2)

We are given that, the equation has real equal roots. So,

=> D (Discriminant) = 0

=> b² - 4ac = 0

=> (4k)² - 4(1)(k² - k + 2) = 0

=> 16k²- 4k² + 4k - 8 = 0

=> 12k² + 4k - 8 = 0

=> 4(3k² + k - 2) = 0

=> 3k² + k - 2 = 0

=> 3k² + (3 - 2)k - 2 = 0

=> 3k² + 3k - 2k - 2 = 0

=> 3k(k + 1) - 2(k + 1) = 0

=> (k + 1)(3k - 2) = 0

Therefore, k = -1 and 2/3

Hope this helps........