Question

Tell me that quetion no. 2 and quetion no.3 plzzz .....Amal answer Mee.......

Answer 1

Ans. In quadrilateral ABCE, diagonal AC divides it in two triangles, ABC and ADC.

In ABC, Semi-perimeter of ABC =  = 6 cm

Using Heron’s formula,

Area of ABC =  

=  =  

Again, In ADC, Semi-perimeter of ADC =  = 7 cm

Using Heron’s formula, Area of ABC =  

=  =  = 2

(approx.)

Now area of quadrilateral ABCD = Area of ABC + Area of ADC

= 6 + 9.2

Area of triangular part I: Here, Semi-perimeter  = 5.5 cm

Therefore, Area =  

=  

=  =  

Area of triangular part II = Length x Breadth  

Area of triangular part III (trapezium):  

=  (AB + DC)  =  (1 + 2)  

=  =  

Area of triangular parts IV & V:  

Total area = 2.4825 + 6.2 + 1.299 + 9