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the answer is option D
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Mark it as brainliest
∵(x²+x-1)(x²+x-1)=(x²+x)²-(1)²=x⁴+2x³+x²-1≠x⁴+x²+1 ∴this answer is wrong
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x⁴+x²+1
=x⁴+x²+1
=x⁴+2x²-x²+1 [∵ x²=2x²-x²]
=(x⁴+2x²+1)-x²
={(x²)²+2×x²×1+(1)²}-(x)²
=(x²+1)²-(x)²[∵ a²+2ab+b²=(a+b)²]
=(x²+1+x)(x²+1-x)[∵a²-b²=(a+b)(a-b)]
=(x²+x+1)(x²-x+1)
∴the factors of x⁴+x²+1 are (x²+x+1)&(x²-x+1).
∴option(3)is correct.
=x⁴+x²+1
=x⁴+2x²-x²+1 [∵ x²=2x²-x²]
=(x⁴+2x²+1)-x²
={(x²)²+2×x²×1+(1)²}-(x)²
=(x²+1)²-(x)²[∵ a²+2ab+b²=(a+b)²]
=(x²+1+x)(x²+1-x)[∵a²-b²=(a+b)(a-b)]
=(x²+x+1)(x²-x+1)
∴the factors of x⁴+x²+1 are (x²+x+1)&(x²-x+1).
∴option(3)is correct.
please mark my answer the brainliest
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