Question

tell me the answer for this question.

Answer 1

let be the no. of the larger no.= x
square of larger no.= x^2
smaller no. =8
so the smaller no
is 8 times= 8x


so
ACC to the question
x^2-8x= 180
solve in equation

x^2-8x-180=0
x^2-18x+10x-180=0
x(x-18)+10x(x-18)=0
so the value of

x= -10, 18

negative no. can not be taken


so the smaller no.
√8x
√8×18
√144
=12

so the two positive no.
is 12,18