Math, asked by Pythagaros, 1 year ago

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Answered by Anonymous
3

Heya!! Math Lover.

ax + by = c ... equation 1

bx + ay = d .... equation 2

€ ax + by = c

Squaring both sides

( ax + by )² = c²

( ax )² + ( by )² + 2abxy = c² ... equation 3

€ bx + ay = d

Squaring both sides

( bx + ay )² = d²

( bx )² + ( ay )² + 2abxy = d²... equation 4

Now, subtract equation 3 from 4

( bx )² + ( ay )² - ( ax )² - ( by )² = d² - c²

( bx )² - ( by )² + ( ay )² - ( ax)² = d² - c²

b² ( x² - y² ) - a² ( x² - y² ) = d² - c²

( x² - y² ) = ( d² - c² ) / ( b² - a² )

HAVE A NYC DAY

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