Question

tell me the answer of this​

Answer 1

Answer:

Hey friend,

Here is the answer you are searching for,

$\frac{1}{x + 2} + \frac{1}{x + 3} = \frac{2}{x + 9} \\ lcm \: of \: denominators \: \\ = (x + 2)(x + 3) \\ = > \frac{1}{x + 2} + \frac{1}{x + 3} = \frac{2}{x + 9} \\ = > \frac{(x + 3) + (x + 2)}{(x + 2)(x + 3)} = \frac{2}{x + 9} \\ = > \frac{2x + 5}{ {x}^{2} + 2x + 3x + 6 } = \frac{2}{x + 9} \\ = > (2x + 5)(x + 9) \ \\ = 2({ {x}^{2} + 5x + 6 } ) \\ = > {2x}^{2} + 5x + 18x \: + 45 \\ = {2x}^{2} + 10x + 12 \\ = > 23x + 45 = 10x + 12 \\ = > 23x - 10x = - 45 + 12 \\ = > 13x = - 33 \\ = > x = \frac{ - 33}{13}$

HOPE IT HELPS YOU.

PLEASE MARK AS BRAINLIEST...