Chemistry, asked by jyotisinghania555, 8 months ago

tell me the answer of this question , please guys​

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Answered by mishtirimjha
1

Answer:

percentage of sulphur =42.10%

Explanation:

Molecular mass of BaSO4 = 137+32+64

=233g

233 g BaSO4 contains 32 g sulphur

0.4813 g BaSO4 contains 32*0.4813 g sulphur

233

Percentage of sulphur = 32*0.4813*100

233*0.157

= 42.10%

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