tell me the answer of this question , please guys
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Answer:
percentage of sulphur =42.10%
Explanation:
Molecular mass of BaSO4 = 137+32+64
=233g
233 g BaSO4 contains 32 g sulphur
0.4813 g BaSO4 contains 32*0.4813 g sulphur
233
Percentage of sulphur = 32*0.4813*100
233*0.157
= 42.10%
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