Question

tell me this question very soon​

Answer 1

Step-by-step explanation:

We know that 5, 12 and 13 are Pythagorean triplets.

$\therefore \: {5}^{2} + {12}^{2} = {13}^{2} \\ \therefore \: {5}^{ \sqrt{4} } + {12}^{ \sqrt{4} } = {13}^{ \sqrt{4} } ...(1) \\ equating \: (1) \: with \: \\ {5}^{ \sqrt{x} } + {12}^{ \sqrt{x} }= {13}^{ \sqrt{x} } \: we \: find : \\ \sqrt{x} = \sqrt{4} \\ \implies \huge \fbox{ x = 4}$

Thus, option b is the correct answer.