Math, asked by stargirlA1, 10 months ago

tell please after few hours is my paper.
Please tell.​

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Answers

Answered by parul682
1

Answer:

(x^4×1/2 y1/2)-4

(x^2 y1/2)^-4

x^2×-4 y^1/2×(-4)

x^-8 y^-2

1/x^8×y^2 this is 1st no.

now the 2nd one

(1/x^1/3 y^6×1/3)^-4

(1/x^1/3 y^2)^-4

1/x^1/3×-4 y^2×-4

1/x^-4/3 y^-8

now reciprocal

x^4/3 y8

now combining the both we get

1/x^8 y^2 ×x^4/3 y^8

x^4/3 y^6/x^8

I think u could understand actually attachment is not going net is slow

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