Question

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Answer 1

$let \: ( \frac{x}{y} + \frac{y}{x} ) = a \\ so \\ 4 {a}^{2} - 23a - 6 \\ = 4 {a}^{2} - 24a + a - 6 \\ = 4a(a - 6) + 1(a - 6) \\ = (4a + 1)(a - 6) \\ = (4 \frac{x}{y} + 4 \frac{y}{x} + 1)( \frac{x}{y} + \frac{y}{x} - 6)$

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