Math, asked by hpzugare, 8 months ago

tell the answer in step by step plzz

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Answered by Anonymous

The given equation is √3X² - 2√2X - 2√3 = 0

Here,

a = √3 , b = -2√2 and c = -2√3.

Discriminant ( D ) = B²-4AC

=> (-2√2)² - 4 × √3 × -2√3

=> 8 + 24

=> 32

✓D = √32 = √2 × 2 × 2 × 2 × 2 = 4√2.

Roots of the given equation are : -B + √D/2A and -B - √D/2A

=> - (-2✓2) + 4√2 / 2√3 and -(-2√2) - 4√2/2√3

=> ( 2√2 + 4√2 ) /2√3 and (2√2 - 4√2 ) /2√3

=> ( 6√2/2√3 ) And ( -2√2/2√3 ).

=> ( 3√2/√3 ) and ( -√2/√3)

=> ( √3 × √3 × √2/✓3) and ( -√2/√3)

=> ( √3 × √2 ) and ( -√2/✓3)

=> ( √6 ) and ( -√2/√3).

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Answered by anukulpathak84

Answer:

1 find b²-4ac

2 then check b²-4ac>0 or<0or=0

3 it gives b²-4ac<0

4 Hence it has imaginary roots

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