tell the force on 2m due to 1m
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The question is quite easy and so is the answer
However
When you draw FBD of block of 2 kg mass There are 3 forces acting on it
(1) N1 - normal force in downward direction due to the weight 3kg and 4 kg simultaneously which is equal to (3+4)*10 N = 70 N
(2) N2 - normal force in upward direction due to block of mass 1 kg which will be calculated later
(3) mg = gravitational force by earth = 2*10 N = 20 N
Since 2 kg bolck is in equilibrium in vertical direction
We can say sum of all the forces on it in vertical direction is zero
So
N1 + N2 + W = 0
N1 = - 70 N (taking upward direction as positive and downward direction as negative )
mg = - 20 N
So
( - 70N ) + ( - 20N ) + N2 = 0
N2 = + 90 N
So N2 is the answer
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