Question

tell this 4yz(z²+6z-16) ÷2y(z+8) pls tell it fast

Answer 1

z2+6z-16
= z2+8z-6z-16
= z(z+8)-2(z+8)
= (z-2)(z+8)

Answer 2

Answer:

The required solution is $2z^2-4z$.

Step-by-step explanation:

The given expression is

4yz(z²+6z-16) ÷ 2y(z+8)

It can be written as

$\frac{4yz(z^2+6z-16)}{2y(z+8)}$

Now factories the numerator.

$\frac{4yz(z^2+8z-2z-16)}{2y(z+8)}$

$\frac{4yz(z(z+8)-2(z+8))}{2y(z+8)}$

$\frac{4yz(z+8)(z-2)}{2y(z+8)}$

Now cancel out the common facotrs.

$2z(z-2)$

$2z^2-4z$

Therefore the required solution is $2z^2-4z$.