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Answer:
0.06349 m3
Step-by-step explanation:
Inner radius of the hemispherical tank (r) = 1 m
Outer radius of the hemispherical tank (R) = 1 + 0.01 = 1.01 m
Volume of iron used to make the hemispherical tank = 2/3πR3 - 2/3πr3
= 2/3π(R3 - r3) = 2/3 x 22/7 [(1.01)3 - 13]
= 44/21(1.0303 - 1) = 44/21 x 0.0303
= 0.06349 m3
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