Math, asked by vivekDwivedi23468, 18 hours ago

Tell this question please specialy vinay​

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Answered by ichchhakuichchha
3

Ans (i)=-x²yz(xy²z-x²z)

-(-1)²×1×2(-1×1²×2-(-1)²×2)

1×2(-1×1×2+1×2)

2(-1×2+2)

2(-2+2)

2×0

0

Ans (ii)=4xz²(-xyz+3yz²)

4(-1)(2)²(-1×1×2+3×1×2²)

-4×4(-2+3×2²)

-16(-2+3×4)

-16(-2+12)

-16×10

-160

Answered by shalinijain643
1

Answer:

1)

-x^2yz ( xy^2-x^2z)

= -(-1×1×2) [(-1×1^2×2-(-1^2×2)]

= 2[-2+2]

= 2[0]

= 0

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