Tell this question please specialy vinay
Attachments:
Answers
Answered by
3
Ans (i)=-x²yz(xy²z-x²z)
-(-1)²×1×2(-1×1²×2-(-1)²×2)
1×2(-1×1×2+1×2)
2(-1×2+2)
2(-2+2)
2×0
0
Ans (ii)=4xz²(-xyz+3yz²)
4(-1)(2)²(-1×1×2+3×1×2²)
-4×4(-2+3×2²)
-16(-2+3×4)
-16(-2+12)
-16×10
-160
Answered by
1
Answer:
1)
-x^2yz ( xy^2-x^2z)
= -(-1×1×2) [(-1×1^2×2-(-1^2×2)]
= 2[-2+2]
= 2[0]
= 0
mark me brainlist
Similar questions