Question

temp. of a body is 400°c. assuming the surrounding temp. to be negligible. at what temp. will body emit double energy radiation ?​

Answer 1

Answer:

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Explanation:

$R=kT^{4}$

$first\:case$

$R=k(623.15)^{4}$

$second\:case$

$2R=kT^{4}$

$2k(623.15)^{4} =kT^{4}$

$T=800K\:approx$

$=526\:approx$

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Answer 2

R=kT⁴

first casefirstcase

R=k(623.15)^{4}R=k(623.15)⁴

2R=kT^{4}2R=kT ⁴

2k(623.15)^{4} =kT^{4}2k(623.15) ⁴

=kT ⁴

T=800K approxT=800Kapprox

=526 approx=526approx