Question

Temperature corresponding to 1 ev translational kinetic energy

Answer 1

Hi there.

Given ⇒
Average Kinetic energy = 1 eV.
K.E. = 1.6 × 10⁻¹⁹ J.

Now, Using the Formula,
Average kinetic energy = 3/2 × k T
where, k = Boltzmann Constant = 1.38 × 10⁻²³ m² kg/s K².
T = Absolute temperature in the kelvin .

∴ T = (2 × K.E.) ÷ (3 × k)
⇒ T = (2 × 1.6 × 10⁻¹⁹) ÷ (3 × 1.38 × 10⁻²³)
⇒ T = 0.773 × 10⁴
∴ T = 7.73 × 10³ K.


Hence, the temperature corresponding to the 1 eV transnational kinetic energy is 7.73 × 10³ K.


Hope it helps.

Answer 2

Solution:-

Temperature corresponding to 1 ev translational kinetic energy is:-

= k.e = 3/2×k.t

= T = 2.k.e/ 3k

$t = \frac{2 \times 1.6 \times {10}^{ - 19} }{3 \times 1.38 \times {10}^{ - 23} } \\ = (7.72 \times {10}^{ 3} ) k$
☆i hope its help☆