Question

The angular momentum and electron in a given orbital s j

Answer 1

according to Bohr

angular momentum of an electron = nh/2(pi)

hence,

mvr = nh/2(pi)

according to question angular momentum is “J”

means 

nh/2(pi) = J

now 

mvr = nh/2(pi)

squaring both sides

m2v2r2 = n2h2/4(pi)2

m2v2r2 = J2

now knietic energy = 1/2mv2

hence,

multiplying both sides my ½

1/2m2v2r2 = J2/2

1/2mv2 = J2/2r2m

Answer 2

Answer:

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Explanation:

According to Bohr,,

Angular momentum of an electron = nh/2(pi)

ngular momentum of an electron = nh/2(pi)hence,

ngular momentum of an electron = nh/2(pi)hence,mvr = nh/2(pi)

According to question angular momentum is “J”

ccording to question angular momentum is “J”means 

ccording to question angular momentum is “J”means nh/2(pi) = J

ccording to question angular momentum is “J”means nh/2(pi) = Jnow 

ccording to question angular momentum is “J”means nh/2(pi) = Jnow mvr = nh/2(pi)

ccording to question angular momentum is “J”means nh/2(pi) = Jnow mvr = nh/2(pi)squaring both sides,,

m2v2r2 = n2h2/4(pi)2

m2v2r2 = n2h2/4(pi)2m2v2r2 = J2

m2v2r2 = n2h2/4(pi)2m2v2r2 = J2now Kinetic energy = 1/2mv2

energy = 1/2mv2hence,

energy = 1/2mv2hence,multiplying both sides my ½

energy = 1/2mv2hence,multiplying both sides my ½1/2m2v2r2 = J2/2

energy = 1/2mv2hence,multiplying both sides my ½1/2m2v2r2 = J2/21/2mv2 = J2/2r2m.

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