Physics, asked by shreyanshpandey1774, 16 days ago

Temperature of a black body is raised from 27⁰C to 327⁰C. The rate of emission of energy from it will become

Answers

Answered by kmrmohitojha840

0

Answer:

Emissivity of black body directly proportional to T^4

E1/E2=T1^4/T2^4=(300/600) ^4=1/16

E2=16E1

Explanation:

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