Question

Temperature of object = 30°C
Final Temperature = 40°C
Specific heat of gold = 0.03 cal
Specific heat of water = 1 cal
Find the Initial Temperature = ?​

Answer 1

Answer:

(40-30)×0.03= 1 ×( T - 40)

= T = 40 + 0.3

T=40.3°C

Explanation:

heat gain = heat loss